--- Day 5: Binary Boarding ---
You board your plane only to discover a new problem: you dropped your boarding pass! You aren't sure which seat is yours, and all of the flight attendants are busy with the flood of people that suddenly made it through passport control.
You write a quick program to use your phone's camera to scan all of the nearby boarding passes (your puzzle input); perhaps you can find your seat through process of elimination.
Instead of zones or groups, this airline uses binary space partitioning to seat people. A seat might be specified like FBFBBFFRLR, where F means "front", B means "back", L means "left", and R means "right".
The first 7 characters will either be F or B; these specify exactly one of the 128 rows on the plane (numbered 0 through 127). Each letter tells you which half of a region the given seat is in. Start with the whole list of rows; the first letter indicates whether the seat is in the front (0 through 63) or the back (64 through 127). The next letter indicates which half of that region the seat is in, and so on until you're left with exactly one row.
For example, consider just the first seven characters of FBFBBFFRLR:
- Start by considering the whole range, rows
0through127. Fmeans to take the lower half, keeping rows0through63.Bmeans to take the upper half, keeping rows32through63.Fmeans to take the lower half, keeping rows32through47.Bmeans to take the upper half, keeping rows40through47.Bkeeps rows44through47.Fkeeps rows44through45.- The final
Fkeeps the lower of the two, row44.
The last three characters will be either L or R; these specify exactly one of the 8 columns of seats on the plane (numbered 0 through 7). The same process as above proceeds again, this time with only three steps. L means to keep the lower half, while R means to keep the upper half.
For example, consider just the last 3 characters of FBFBBFFRLR:
- Start by considering the whole range, columns
0through7. Rmeans to take the upper half, keeping columns4through7.Lmeans to take the lower half, keeping columns4through5.- The final
Rkeeps the upper of the two, column5.
So, decoding FBFBBFFRLR reveals that it is the seat at row 44, column 5.
Every seat also has a unique seat ID: multiply the row by 8, then add the column. In this example, the seat has ID 44 * 8 + 5 = 357.
Here are some other boarding passes:
BFFFBBFRRR: row70, column7, seat ID567.FFFBBBFRRR: row14, column7, seat ID119.BBFFBBFRLL: row102, column4, seat ID820.
As a sanity check, look through your list of boarding passes. What is the highest seat ID on a boarding pass?